tolong dibantu dengan menggunakan caranya, terimakasih
Jawaban:
1. pH = 2-log2
2. pH = 3-log4
3. pH = 3-log8
Langkah Pengerjaan:
1.
[H⁺] = M.Valensi Asam
[H⁺] = 0,02.1
[H⁺] = 0,02 = 2.10⁻²
pH = -log[H⁺]
pH = -log2.10⁻²
pH = 2-log2
2.
M = n/V
M = 0,002/0,5
M = 0,004 M
[H⁺] = M.Valensi Asam
[H⁺] = 0,004.1
[H⁺] = 0,004 = 4.10⁻³
pH = -log[H⁺]
pH = -log4.10⁻³
pH = 3-log4
3.
n = m/Mr
n = 4,9/(2.1+32+4.16)
n = 4,9/98
n = 0,05 mol
M = n/V
M = 0,004/1
M = 0,004 M
[H⁺] = M.Valensi Asam
[H⁺] = 0,004.2
[H⁺] = 0,008 = 8.10⁻³
pH = -log[H⁺]
pH = -log8.10⁻³
